Integrand size = 24, antiderivative size = 24 \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^3 \arctan (a x)^{5/2}} \, dx=-\frac {2}{3 a c^3 x^2 \left (1+a^2 x^2\right )^2 \arctan (a x)^{3/2}}+\frac {8}{3 a^2 c^3 x^3 \left (1+a^2 x^2\right )^2 \sqrt {\arctan (a x)}}+\frac {8}{c^3 x \left (1+a^2 x^2\right )^2 \sqrt {\arctan (a x)}}+\frac {30 a \sqrt {\arctan (a x)}}{c^3}+\frac {5 a \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )}{c^3}+\frac {20 a \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )}{c^3}+\frac {8 \text {Int}\left (\frac {1}{x^4 \left (c+a^2 c x^2\right )^3 \sqrt {\arctan (a x)}},x\right )}{a^2}+\frac {80}{3} \text {Int}\left (\frac {1}{x^2 \left (c+a^2 c x^2\right )^3 \sqrt {\arctan (a x)}},x\right ) \]
-2/3/a/c^3/x^2/(a^2*x^2+1)^2/arctan(a*x)^(3/2)+5/2*a*FresnelC(2*2^(1/2)/Pi ^(1/2)*arctan(a*x)^(1/2))*2^(1/2)*Pi^(1/2)/c^3+20*a*FresnelC(2*arctan(a*x) ^(1/2)/Pi^(1/2))*Pi^(1/2)/c^3+8/3/a^2/c^3/x^3/(a^2*x^2+1)^2/arctan(a*x)^(1 /2)+8/c^3/x/(a^2*x^2+1)^2/arctan(a*x)^(1/2)+30*a*arctan(a*x)^(1/2)/c^3+8*U nintegrable(1/x^4/(a^2*c*x^2+c)^3/arctan(a*x)^(1/2),x)/a^2+80/3*Unintegrab le(1/x^2/(a^2*c*x^2+c)^3/arctan(a*x)^(1/2),x)
Not integrable
Time = 6.49 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^3 \arctan (a x)^{5/2}} \, dx=\int \frac {1}{x^2 \left (c+a^2 c x^2\right )^3 \arctan (a x)^{5/2}} \, dx \]
Not integrable
Time = 1.49 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {5503, 27, 5503, 5439, 3042, 3793, 2009, 5560}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{x^2 \arctan (a x)^{5/2} \left (a^2 c x^2+c\right )^3} \, dx\) |
\(\Big \downarrow \) 5503 |
\(\displaystyle -4 a \int \frac {1}{c^3 x \left (a^2 x^2+1\right )^3 \arctan (a x)^{3/2}}dx-\frac {4 \int \frac {1}{c^3 x^3 \left (a^2 x^2+1\right )^3 \arctan (a x)^{3/2}}dx}{3 a}-\frac {2}{3 a c^3 x^2 \left (a^2 x^2+1\right )^2 \arctan (a x)^{3/2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {4 a \int \frac {1}{x \left (a^2 x^2+1\right )^3 \arctan (a x)^{3/2}}dx}{c^3}-\frac {4 \int \frac {1}{x^3 \left (a^2 x^2+1\right )^3 \arctan (a x)^{3/2}}dx}{3 a c^3}-\frac {2}{3 a c^3 x^2 \left (a^2 x^2+1\right )^2 \arctan (a x)^{3/2}}\) |
\(\Big \downarrow \) 5503 |
\(\displaystyle -\frac {4 a \left (-10 a \int \frac {1}{\left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx-\frac {2 \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a x \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}\right )}{c^3}-\frac {4 \left (-14 a \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a x^3 \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}\right )}{3 a c^3}-\frac {2}{3 a c^3 x^2 \left (a^2 x^2+1\right )^2 \arctan (a x)^{3/2}}\) |
\(\Big \downarrow \) 5439 |
\(\displaystyle -\frac {4 a \left (-\frac {2 \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-10 \int \frac {1}{\left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}d\arctan (a x)-\frac {2}{a x \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}\right )}{c^3}-\frac {4 \left (-14 a \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a x^3 \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}\right )}{3 a c^3}-\frac {2}{3 a c^3 x^2 \left (a^2 x^2+1\right )^2 \arctan (a x)^{3/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {4 a \left (-\frac {2 \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-10 \int \frac {\sin \left (\arctan (a x)+\frac {\pi }{2}\right )^4}{\sqrt {\arctan (a x)}}d\arctan (a x)-\frac {2}{a x \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}\right )}{c^3}-\frac {4 \left (-14 a \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a x^3 \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}\right )}{3 a c^3}-\frac {2}{3 a c^3 x^2 \left (a^2 x^2+1\right )^2 \arctan (a x)^{3/2}}\) |
\(\Big \downarrow \) 3793 |
\(\displaystyle -\frac {4 a \left (-\frac {2 \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-10 \int \left (\frac {\cos (2 \arctan (a x))}{2 \sqrt {\arctan (a x)}}+\frac {\cos (4 \arctan (a x))}{8 \sqrt {\arctan (a x)}}+\frac {3}{8 \sqrt {\arctan (a x)}}\right )d\arctan (a x)-\frac {2}{a x \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}\right )}{c^3}-\frac {4 \left (-14 a \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a x^3 \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}\right )}{3 a c^3}-\frac {2}{3 a c^3 x^2 \left (a^2 x^2+1\right )^2 \arctan (a x)^{3/2}}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -\frac {4 a \left (-\frac {2 \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a x \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}-10 \left (\frac {1}{8} \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )+\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )+\frac {3}{4} \sqrt {\arctan (a x)}\right )\right )}{c^3}-\frac {4 \left (-14 a \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a x^3 \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}\right )}{3 a c^3}-\frac {2}{3 a c^3 x^2 \left (a^2 x^2+1\right )^2 \arctan (a x)^{3/2}}\) |
\(\Big \downarrow \) 5560 |
\(\displaystyle -\frac {4 a \left (-\frac {2 \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a x \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}-10 \left (\frac {1}{8} \sqrt {\frac {\pi }{2}} \operatorname {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\arctan (a x)}\right )+\frac {1}{2} \sqrt {\pi } \operatorname {FresnelC}\left (\frac {2 \sqrt {\arctan (a x)}}{\sqrt {\pi }}\right )+\frac {3}{4} \sqrt {\arctan (a x)}\right )\right )}{c^3}-\frac {4 \left (-14 a \int \frac {1}{x^2 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx-\frac {6 \int \frac {1}{x^4 \left (a^2 x^2+1\right )^3 \sqrt {\arctan (a x)}}dx}{a}-\frac {2}{a x^3 \left (a^2 x^2+1\right )^2 \sqrt {\arctan (a x)}}\right )}{3 a c^3}-\frac {2}{3 a c^3 x^2 \left (a^2 x^2+1\right )^2 \arctan (a x)^{3/2}}\) |
3.11.73.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> In t[ExpandTrigReduce[(c + d*x)^m, Sin[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f , m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1]))
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*((d_) + (e_.)*(x_)^2)^(q_), x_ Symbol] :> Simp[d^q/c Subst[Int[(a + b*x)^p/Cos[x]^(2*(q + 1)), x], x, Ar cTan[c*x]], x] /; FreeQ[{a, b, c, d, e, p}, x] && EqQ[e, c^2*d] && ILtQ[2*( q + 1), 0] && (IntegerQ[q] || GtQ[d, 0])
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^ 2)^(q_), x_Symbol] :> Simp[x^m*(d + e*x^2)^(q + 1)*((a + b*ArcTan[c*x])^(p + 1)/(b*c*d*(p + 1))), x] + (-Simp[c*((m + 2*q + 2)/(b*(p + 1))) Int[x^(m + 1)*(d + e*x^2)^q*(a + b*ArcTan[c*x])^(p + 1), x], x] - Simp[m/(b*c*(p + 1)) Int[x^(m - 1)*(d + e*x^2)^q*(a + b*ArcTan[c*x])^(p + 1), x], x]) /; F reeQ[{a, b, c, d, e, m}, x] && EqQ[e, c^2*d] && IntegerQ[m] && LtQ[q, -1] & & LtQ[p, -1] && NeQ[m + 2*q + 2, 0]
Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(u_.), x_Symbol] :> Unintegrab le[u*(a + b*ArcTan[c*x])^p, x] /; FreeQ[{a, b, c, p}, x] && (EqQ[u, 1] || M atchQ[u, ((d_.) + (e_.)*x)^(q_.) /; FreeQ[{d, e, q}, x]] || MatchQ[u, ((f_. )*x)^(m_.)*((d_.) + (e_.)*x)^(q_.) /; FreeQ[{d, e, f, m, q}, x]] || MatchQ[ u, ((d_.) + (e_.)*x^2)^(q_.) /; FreeQ[{d, e, q}, x]] || MatchQ[u, ((f_.)*x) ^(m_.)*((d_.) + (e_.)*x^2)^(q_.) /; FreeQ[{d, e, f, m, q}, x]])
Not integrable
Time = 0.10 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92
\[\int \frac {1}{x^{2} \left (a^{2} c \,x^{2}+c \right )^{3} \arctan \left (a x \right )^{\frac {5}{2}}}d x\]
Exception generated. \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^3 \arctan (a x)^{5/2}} \, dx=\text {Exception raised: TypeError} \]
Exception raised: TypeError >> Error detected within library code: inte grate: implementation incomplete (constant residues)
Not integrable
Time = 40.83 (sec) , antiderivative size = 66, normalized size of antiderivative = 2.75 \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^3 \arctan (a x)^{5/2}} \, dx=\frac {\int \frac {1}{a^{6} x^{8} \operatorname {atan}^{\frac {5}{2}}{\left (a x \right )} + 3 a^{4} x^{6} \operatorname {atan}^{\frac {5}{2}}{\left (a x \right )} + 3 a^{2} x^{4} \operatorname {atan}^{\frac {5}{2}}{\left (a x \right )} + x^{2} \operatorname {atan}^{\frac {5}{2}}{\left (a x \right )}}\, dx}{c^{3}} \]
Integral(1/(a**6*x**8*atan(a*x)**(5/2) + 3*a**4*x**6*atan(a*x)**(5/2) + 3* a**2*x**4*atan(a*x)**(5/2) + x**2*atan(a*x)**(5/2)), x)/c**3
Exception generated. \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^3 \arctan (a x)^{5/2}} \, dx=\text {Exception raised: RuntimeError} \]
Timed out. \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^3 \arctan (a x)^{5/2}} \, dx=\text {Timed out} \]
Not integrable
Time = 0.68 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^3 \arctan (a x)^{5/2}} \, dx=\int \frac {1}{x^2\,{\mathrm {atan}\left (a\,x\right )}^{5/2}\,{\left (c\,a^2\,x^2+c\right )}^3} \,d x \]